plaster wikipedia. 0. 0. Volume of plaster = Area X Thickness = 10 sq.m. Generally, in any plastering work plasterers are used natural sand, crushed stone sand or crushed gravel sand. View all Did Deadpool kill everyone in the Marvel Universe? Assume we need to calculate plastering material quantity for 10 X 10 m ceiling. Example. • 1:4 – for ceiling and external plaster. What type of sand is used for plastering? Cement Mortar Required: Plastering thickness 12 mm = 12/1000 = 0.012m. For ceiling plastering, the ratio of Cement : Sand = 1 : 4. ∵Volume of plaster = Area of plaster x Thickness of plaster. Cancel Unsubscribe. For suppose 1:3 ratio refers to 1 part of cement and 3 parts of sand in a mortar. For wall plastering, the ratio of Cement : Sand = 1 : 6. calculation of cement and sand for plastering excel sheet. In pointing, we use just cement mortar. Let us take an example of a wall to be plastered: Length of wall = 2m. What is the ratio of cement to sand for plastering? • 1:5 – the ratio proved to be good as brickwork mortar. Ants are constantly, How dangerous is pest control? Mortar ratio = 1:6 where 1 is cement and 6 part is sand. Once the quantities are known, it is easy to estimate the cost with the rates prevailing in your area. Plastering Deductions as per IS Code 1200. For wall plaster generally ratio we use = 1: 6 (1 part of cement and 6 part of sand). Add 20% extra Quantity for Filling of joints, Depressions & Wastage. Plaster is a material used in building for the purposes such as protection, decoration, coating of walls, ceilings, moulding etc. Plaster thickness = 12 mm = 0.012 m Cement density = 1440 kg/m 3 1 m3 = 35.3147 ft3 Suggested Plaster Thickness 12 mm for internal walls or brick wall plain surface. On a brick wall never do plastering of thickness more than 12 or 15mm. Calculation of area of walls for plaster. Quick Answer: Does Ceramic Coating Prevent Rock Chips? Calcuate area by LxB method. For opening of size 0.5m2 to 3m2 area, deduction is made on one face of the wall. (This is wet volume of cement mortar (after mixing water) but we need dry volume. Therefore, volume of mortar = 5.16 + [5.16 x (30/100)] 15 mm for 4” or 9” brick wall rough surface 20 mm for two plaster layers normally utilized for external walls (see below for a more extensive internal plastering estimator). Mortar quantity =0. www.quora.com What is the strongest form of Hulk? Here, the length of the wall is taken as 6 meter, height is taken as 3 meter and thickness is taken as 12 mm = 0.012 meter. = 12/1000 = 0.012m. Add 20% extra Quantity for Filling of joints, Depressions & Wastage. 0. Basically river sand are used for any plastering work. Plastering thickness = 20 mm. OPC is available in two grades — 43 and 53. Does Fimo clay dry out? 0. 20.8K Shares . For openings of size above 3m2, deduction is made on both faces of the wall, but the area of sill, jamb and soffits of the opening is added. So the first stage is just to measure the height and length of the wall in metres, multiply them together to give the area in square metres, and then multiply this by 120. After calculating the volume we just find the quantity of cement, Sand and water required in this plasterwork according to these given data. Find out the total volume of plastering by multiplying area with thickness. a checklist for quality plaster work last part a civil. On this page, you can calculate the quantity of cement and sand required for plastering a given wall area. And for outer plastering mix it in the ratio of 1:4. PlasterArea =Length×Width PlasterArea = Length × Width Plaster Area =10× 10 Plaster Area = 10 × 10 Plaster Area =100.00m2 Plaster Area = 100.00 m 2 Plaster Area =1076.39ft2 Plaster Area = 1076.39 ft 2 Let us suppose, Mortar ratio = 1:6 where 1 is cement and 6 part is sand. civil at work external plaster check list. Make sure to follow proper plastering work procedure; Plastering Calculation. Plaster, a pasty composition (as of lime or gypsum, water, and sand) that hardens on drying and is used for coating walls, ceilings, and partitions. Thickness of plaster varies according to type of work generally it is 6mm and 12-15mm. Plastering Calculation Assume we need to calculate plastering material quantity for 10 X 10 m ceiling. General Notes. You will take 4 wall sides of room and ceiling. Consider the ratio and thickness of plastering Calculate the Total Volume of … The plastering is done at both sides of surface (both inside and outside). For openings exceeding 0.5 sq m but not exceeding 3 sq m and when both faces are plastered with same type of plaster each deduction shall be made for one face only, and the other face shall be allowed for jambs, soffits and sills which shall not be measured. On this page, you can calculate the quantity of cement and sand required for plastering a given wall area. The plastering is usually done in two layers (two coats): The first coat of plastering is laid with the thickness of minimum 12mm (ranges between 12-15mm) and this coat is called as a Rough coat or Primary coat. Empty contents of cement bag and mix thoroughly with sand and stone. View all How can you protect against rock chips? ∵Volume of plaster = Area of plaster x Thickness of plaster. Volume of cement mortar required = ( Plastering Area x thickness ) = 100 m 2 x 0.012m = 1.2 m 3. Quantity of sand required for 10 sqm internal brick wall plastering. How much cement is required to plaster a wall? Recommended Cement Mortar ratio for Plastering: Mix in a wheelbarrow, on a plastic sheet or on a pre-wet surface using clean, drinkable water wherever possible. Step-1:Calculate the dry volume of cement and sand mixture required. Thickness of plaster to be used = 20mm. of mortar / mortar proportion, Therefore, Cement in bags = 0.103 x 30 = 3.09 say 4 bags, Actual area of wall = (2.50 x 2 + 3.00 x 2) x 3 – W – D1 – D1, = (5 + 6) x 3 – (1.20 x 1.20) – (1.20 x 2.10) - (1.20 x 2.10, Volume of mortar required = 0.318 + [0.317 x (30/100)], Therefore, Dry volume required = 0.413 + [0.413 x (25/100)], Actual area of wall = (5.70 x 2 + 2.50 x 2) x 3 – W – D1 – D, = (11.4 + 5) x 3 – (1.20 x 1.20) – (0.90 x 2.10) – (1.20 x 2.10), Volume of mortar required = 0.520 + [0.520 x (30/100)], Therefore, Dry volume required = 0.676 + [0.676 x (25/100)], Therefore, Cement in bags = 0.169 x 30 = 5.07 say 6 bags, Actual area of wall = (5.00 x 2 + 3.60 x 2) x 3 – W – W – D2 – D, = (10 + 7.2) x 3 – (1.20 x 1.20) – (1.20 x 1.20) - (0.75 x 2.10) – (1.20 x 2.10), Volume of mortar required = 5.355 + [5.335 x (30/100)], Therefore, Dry volume required = 6.96 + [6.96 x (25/100)], Therefore, Cement in bags = 1.74 x 30 = 52.2 say 53 bags, Actual area of wall = (5.70 x 2 + 4.10 x 2) x 3 – W – W - W – D – D - D, = (11.4 + 8.2) x 3 – (1.20 x 1.20) – (1.20 x 1.20) – (1.20 x 1.20) - (1.20 x 2.10) - (1.20 x 2.10) - (1.20 x 2.10), = 58.8 – 1.44 – 1.44 -  1.44 – 2.52 – 2.52 – 2.52, Volume of mortar required = 5.63 + [5.63 x (30/100)], Therefore, Dry volume required = 7.31 + [7.31 x (25/100)], Therefore, Cement in bags = 1.82 x 30 = 54.78 say 55 bags, Actual area of wall = (4.20 x 2 + 3.00 x 2) x 3 – W – W – D – D - D, = (8.4 + 6) x 3 – (1.20 x 1.20) – (1.20 x 1.20) - (1.20 x 2.10) - (1.20 x 2.10) - (1.20 x 2.10), = 43.2 – 1.44 – 1.44 – 2.52 – 2.52 – 2.52, Volume of mortar required = 3.93 + [3.93 x (30/100)], Therefore, Dry volume required = 5.10 + [5.10 x (25/100)], Therefore, Cement in bags = 1.27 x 30 = 38.1 say 39 bags, Actual area of wall = (3.60 x 2 + 5.00 x 2) x 3 – W – W - W – D – D2, = (7.2 + 10) x 3 – (1.20 x 1.20) – (1.20 x 1.20) - (1.20 x 1.20) - (1.20 x 2.10) – (0.75 x 2.10), = 51.6 – 1.44 – 1.44 – 1.44 - 2.52 – 1.575, Volume of mortar required = 5.18 + [5.18 x (30/100)], Therefore, Dry volume required = 6.73 + [6.73 x (25/100)], Therefore, Cement in bags = 1.68 x 30 = 50.4 say 51 bags, Actual area of wall = (2.60 x 2 + 1.00 x 2) x 3 – V – V1 - D2, = (5.20 + 2) x 3 – (0.75 x 0.90) – (1.20 x 1.20) - (0.75 x 2.10), Volume of mortar required = 1.46 + [1.46 x (30/100)], Therefore, Dry volume required = 1.89 + [1.89 x (25/100)], Therefore, Cement in bags = 0.472 x 30 = 14.17 say 15 bags, Actual area of wall = (1.75 x 2 + 0.90 x 2) x 3 – V1 - D2, = (3.5 + 1.8) x 3 – (1.20 x 1.20) - (0.75 x 2.10), Volume of mortar required = 1.54 + [1.54 x (30/100)], Therefore, Dry volume required = 2.002 + [2.002 x (25/100)], Therefore, Cement in bags = 0.5 x 30 = 15 bags. Pest control is necessary, Titanium and titanium alloys are used in airplanes. Mortar ratio = 1:6 where 1 is cement and 6 part is sand. It is also good for internal plaster. 143. Our online tools will provide quick answers to your calculation and conversion needs. The thickness of plaster is between = 12 mm to 15 mm. Quick Answer: Do Termites Eat Hardwood Floors? Make sure you know the required plastering thickness Inner Wall Plastering – 12-15 mm; Outer wall plastering – 20mm; Ceiling Plastering – 10-12 mm; Plastering Calculation. Hence cement for plaster is 0.7879 number of bags of cement required for 10 sqm of internal brick wall plastering. Apply deductions of windows and doors in last to get final quantity of plaster. Plastering refers to protecting a wall or ceiling by laying a plaster (Cement plaster). Here is the useful Plaster calculator to calculate cement and sand for plastering. 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